Create a method that takes a string parameter and looks for pairs of strings in the code, breaking the string up using spaces as the delimiter. There are two types of pairs, combinations and adjacent, and you'll need to find a count of each. Adjacent pairs appear alongside each other, while combination pairs cover every permutation that can be found of pairing the strings.
So if you have a string
So if you have a string
dzone java dzone dzone javascript java
the results would be
dzone has 1 adjacent pair
dzone has 3 combination pairs (0,2) (0,3) (2,3)
java has 1 combination pair (1,5)
dzone has 3 combination pairs (0,2) (0,3) (2,3)
java has 1 combination pair (1,5)
Моё решение на Scala:
def hasRepeats( n: Int) = { def innerHasRepeats( s: List[Char]):Boolean = s match { case a::b::tail => if( a == b) true else innerHasRepeats( b::tail) case _ => false } innerHasRepeats( n.toString.toList ) } (45 to 4578).filter( !hasRepeats(_) == true).size
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